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Q.
The locus of the mid-points of chords of the circle $ x^2 + y^2 = 4$ which subtends a right angle at the origin is
IIT JEEIIT JEE 1984Conic Sections
Solution:
We have to find locus of mid-point of chord and we know perpendicular from centre bisects the chord.
$\therefore \angle O A C=45^{\circ}$
In $\triangle O A C, \frac{O C}{O A}=\sin 45^{\circ} \Rightarrow O C=\frac{2}{\sqrt{2}}=\sqrt{2}$
Also, $\sqrt{h^{2}+k^{2}}=O C^{2}$
Hence, $x^{2}+y^{2}=2$ is required equation of locus of mid-point of chord subtending right angle at the centre.