Thank you for reporting, we will resolve it shortly
Q.
The latent heat of vaporisation of water is $2240 \,J$. If the work done in the process of vaporization of $1\,g$ is $168 \,J$, then increase in internal energy will be
From first law of thermodynamics, we have
$\Delta U=Q-W$
Which states that if an amount of heat $Q$ is given to a system, a part of it will be used in increasing the internal energy $(\Delta U)$ of the system and the rest in doing work $(W)$
$\therefore $ We have $Q=M L=1 \times 2240\, J$
and $W=168\,J$
$\therefore \Delta U=2240-168=2072\, J$