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Q.
The angle at which the curve $y = ke ^{ kx }$ intersects the $y$-axis is:
Application of Derivatives
Solution:
Given $y = ke ^{ kx }$. The curve
intersects the $y$ -axis at $(0, k )$
So, $\left(\frac{ dy }{ dx }\right)_{(0, k )}= k ^{2}$
If $\theta$ is the angle at which 1 the given curve intersects the $y$-axis, then
$\tan\left(\frac{\pi}{2} -\theta \right) = \frac{k^2 - 0}{1 + 0.k^2} = k^2$
$\Rightarrow \theta = cot^{-1} (k^2)$