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Q. An electric power station transmits $100 \,MW$ power through long and thin cable. It the transmission is at (i) $20000 \,V$, (ii) $200 \,V$, in which case would be less power loss?

AFMCAFMC 2004

Solution:

Power dissipated is given by
$P=V I$
where, $V$ is voltage and $I$ is current
First case,
$I_{1}=\frac{P}{V_{1}}=\frac{100 \times 10^{6}}{20000}=5000\, A$
Second case,
$I_{2}=\frac{P}{V_{2}}=\frac{100 \times 10^{6}}{200}=500000\, A$
Also power dissipated is given by
$P=I^{2} R$
where, $R$ is resistance of the cable.
$\therefore P_{1}=(5000)^{2} R=25 \times 10^{6} R$
$P_{2}=(500000)^{2} R=25 \times 10^{10} R$
$\Rightarrow P_{1} < P_{2}$