Q.
In the figure, potential difference between A and B is :
Solution:
$\frac{30-V_{A}}{10}+\frac{0-V_{A}}{10}+\frac{0-V_{A}}{10} = 0$
$3 = \frac{3V_{A}}{10}$
$V_{A} = 10\,V$

Solution: