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Q. In dihybrid crosses, the $F _{1}$ heterozygous plants are self fertilised to produce an $F _{2}$ generation and if offsprings are computed in Punnett square the phenotypic $F _{2}$ ratio as per Mendel's independent assortment will yield

Principles of Inheritance and Variation

Solution:

$F_2$ phenotypic ratio is obtained on the basis of phenotypic character shown by the offsprings produced when $F_1$, hybrid is self-crossed. For example, in a dihybrid cross the cross between homozygous pea plant having round and yellow seeds and homozygous pea plant having wrinkled green seed, $F_1$, hybrid have phenotype round and yellow. When $F_1$, hybrid is selfed it gives phenotypic ratio $9 : 3 : 3 : 1 ::$ round yellow : round green : wrinkled yellow : wrinkled green.