Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. If the number of all possible permutations of the letters of the word MATHEMATICS in which the repeated letters are not together is $982(X)$, then $X=$

TS EAMCET 2020

Solution:

Total number of words that can be formed with the letters of the word 'MATHEMATICS'
$=\frac{11 !}{2 ! 2 ! 2 !}=4989600$
Number of words in which all the repeated letters are together
$=8 ! \times \frac{2 !}{2 !} \times \frac{2 !}{2 !} \times \frac{2 !}{2 !}=8 !=40320$
$\therefore $ Required words $=4989600-40320=4949280$
It is given that $982(X)=4949280$
$\Rightarrow X=\frac{4949280}{982}=5040$