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Q. If $f(x) = x \, \tan^{-1} x,$ then $f' (1)$ equals

Limits and Derivatives

Solution:

$f'\left(x\right) = \frac{x}{1+x^{2}} + \tan^{-1}x$
$ \Rightarrow f'\left(1\right) = \frac{1}{2} + \tan^{-1} 1 = \frac{1}{2} + \frac{\pi}{4} .$