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Q. If $A = \left\{x\,\epsilon\,R : \left|x\right| < 2\right\}$ and $B=\left\{x\,\epsilon\,R : \left|x-2\right| \ge 3\right\};$ then :

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Solution:

$A : x \in \left(-2, 2\right); B : x \in (-\infty, -1] \cup [5, \infty)$
$\Rightarrow B - A = R - \left(-2, 5\right)$

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