Question

At $300\, K$, the two solutions of glucose $A$ and $B$ with respective concentration $0.01\, M$ and $0.001\, M$ are separated by semipermeable membrane. How much external pressure is needed to be applied and on which solution so as to prevent osmosis?

• A. 0.2463 atm pressure is applied on solution B
• B. 0.2217 atm pressure is applied on solution $A$
• C. 0.0246 atm pressure is applied on solution B
• D. 0.0217 atm pressure is applied on solution A

Answer 1

Answer: (B)

$p _{ A }=0.01 \times 0.082 \times 300=0.2463 \,atm$

$p_{B}=0.001 \times 0.082 \times 300=0.02463 \,atm$

The movement of solvent particles will occur from dilute solution (B) to A. Hence, the pressure of $(0.2463-0.02463=0.2216 \,atm.)$ should be applied on concentrated solution i.e., solution A.