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Q. Assertion : $2-$ bromobutane on reaction with sodium ethoxide in ethanol gives $1-$ butene as a major product.
Reason : $1-$ butene is more stable than $2-$ butene.

AIIMSAIIMS 2004Hydrocarbons

Solution:

$2$-bromobutane undergo dehydrohalogenation in presence of strong alkali like sodium ethoxide in ethanol. The elimination is according to Saytzeff rule-"During dehydrohalogenation $H$ is eliminated so as to form more alkylated alkene i.e., from the carbon atom which has less $H$ atoms.
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$2$-butene is more stable than $1$-butene due to presence of large number of hyperconjugating structures of $2$-butene.