Q.
A thermodynamic system is taken from an initial state $i$ with internal energy $U _{ i }=100 \,J$ to the final state $f$ along two different paths iaf and $ibf$, as schematically shown in the figure. The work done by the system along the paths $a f,ib$ and $bf$ are $W _{ af }=200 \,J , W _{ ib }=50 \,J$ and $W _{ bf }=100\, J$ respectively. The heat supplied to the system along the path iaf, $ib$ and $bf$ are $Q _{ \text{iaf}}$, $Q _{\text{ib }}$ and $Q _{\text {bf }}$ respectively. If the internal energy of the system in the state $b$ is $U _{ b }=200 \,J$ and $Q _{\text {iaf }}=500 \,J$, the ratio $Q _{\text{bf}} / Q _{\text{ib}}$ is
Solution:
$U _{ b }=200\, J ,$
$ U _{ i }=100\, J$
Process iaf
Process
W(in Joule)
$\Delta U$ ( in Joule )s
Q(in Joule)
ia
0
af
200
Net
300
200
500
$\Rightarrow U _{ f }=400$
Joule Process ibf
Process
W(in Joule)
$\Delta U$ ( in Joule )
Q(in Joule)
ib
100
50
150
bf
200
100
300
Net
300
150
450
Process | W(in Joule) | $\Delta U$ ( in Joule )s | Q(in Joule) |
---|---|---|---|
ia | 0 | ||
af | 200 | ||
Net | 300 | 200 | 500 |
Process | W(in Joule) | $\Delta U$ ( in Joule ) | Q(in Joule) |
---|---|---|---|
ib | 100 | 50 | 150 |
bf | 200 | 100 | 300 |
Net | 300 | 150 | 450 |