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Q. A solid compound $X$ on heating gives $CO_2$ gas and a residue. The residue mixed with water forms $Y$. On passing an excess of $CO_2$ through $Y$ in water, a clear solution $Z$ is obtained. On boiling $Z$, compound $X$ is reformed. The compound $X$ is

AIPMTAIPMT 2004The s-Block Elements

Solution:

Compound X is $CaCO_3$
$^{CaCO_3}_{X}\xrightarrow{\Delta} ^{CaO}_{Residue} + CO_2\uparrow$
$^{CaO}_{Residue}+H_2O \longrightarrow Ca(OH_2)$
$^{Ca(OH)_2 }_{Y}+\,{}^{CO_2}_{Excess}+H_2O \longrightarrow \,{}^{Ca(HCO_3)_2}_{Z}$
$^{Ca(HCO_3)_2}_{Z} \xrightarrow{\Delta}\,{}^{CaCO_3}_{X}+H_2O+CO_2 \uparrow$