1. Tardigrade
  2. Question
  3. Physics
  4. A non-hookian spring has force F=-k x2, where k is the spring constant and x is the displacement from its unstretched position. For the system shown, a mass m connected to an unstretched spring is initially at rest. If the distance upto which the spring extends before the system momentarily comes to rest is ((p m g/q k))1 / 2, then find (p+q). Assume that all surfaces as well as the pulley are frictionless.

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. A non-hookian spring has force $F=-k x^{2}$, where $k$ is the spring constant and $x$ is the displacement from its unstretched position. For the system shown, a mass $m$ connected to an unstretched spring is initially at rest. If the distance upto which the spring extends before the system momentarily comes to rest is $\left(\frac{p m g}{q k}\right)^{1 / 2}$, then find $(p+q)$. Assume that all surfaces as well as the pulley are frictionless.Physics Question Image

Work, Energy and Power

Solution:

$m g x \cos 60^{\circ}=\int\limits_{0}^{x} k x^{2} d x$