1. Tardigrade
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  3. Physics
  4. A lift is moving down with acceleration a. A man in the lift drops a ball inside the lift. The acceleration of the ball as observed by the man in the lift and a man standing stationary on the ground are respectively

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Q. A lift is moving down with acceleration $a$. A man in the lift drops a ball inside the lift. The acceleration of the ball as observed by the man in the lift and a man standing stationary on the ground are respectively

AIEEEAIEEE 2002Laws of Motion

Solution:

Apparent weight of ball
$w^{\prime}=w-R$
$R=m a$ (acts upward)
$w^{\prime}=m g-m a=m(g-a)$
Hence, apparent acceleration in the lift is $g-a$. Now if the man is standing stationary on the ground, then the apparent acceleration of the falling ball is $g$.