1. Tardigrade
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  4. A 2 kg steel rod of length 0.6 m is clamped on a table vertically at its lower end and is free to rotate in vertical plane. The upper end is pushed so that the rod falls under gravity, Ignoring the friction due to clamping at its lower end, the speed of the free end of rod when it passes through its lowest ldots ldots ldots ms -1 .(. Take g =10 ms -2 )

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Q. A $2\, kg$ steel rod of length $0.6 \,m$ is clamped on a table vertically at its lower end and is free to rotate in vertical plane. The upper end is pushed so that the rod falls under gravity, Ignoring the friction due to clamping at its lower end, the speed of the free end of rod when it passes through its lowest $\ldots \ldots \ldots ms ^{-1} .\left(\right.$
Take $g =10 \,ms ^{-2}$ )

JEE MainJEE Main 2021System of Particles and Rotational Motion

Solution:

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by energy conservation $mg \ell=\frac{1}{2} I \omega^{2}$
$=\frac{1}{2} \frac{ m \ell^{2}\,\omega^{2}}{3}$
$\Rightarrow \omega=\sqrt{\frac{6 g }{\ell}}$
Speed $v =\omega r =\omega \ell=\sqrt{6 g \ell}$
$v =\sqrt{6 \times 10 \times .6}$
$=6 \,m / s$