Question

$ZnC{l}_2$ in Lucas reagent is

• A. Lewis acid
• B. Lewis base
• C. Both (A) and (B)
• D. None of these

Answer 1

Answer: (A)

$\underset{\text{Lewis acid}}{ZnC{l}_2}+2HCl\to H_{2}ZnC{l}_4\stackrel{ROH}{\to }R-O^{+}{H}_2\stackrel{Cl}{\to }RCl+H_{2}O$