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Question
Chemistry
ZnCl2 in Lucas reagent is
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Q. $ZnCl_2$ in Lucas reagent is
Alcohols Phenols and Ethers
A
Lewis acid
41%
B
Lewis base
27%
C
Both (A) and (B)
26%
D
None of these
6%
Solution:
$\underset{\text{Lewis acid}}{ZnCl_2} + 2HCl \rightarrow H_2 ZnCl_4 \xrightarrow{ROH} R-O^+ H_2 \xrightarrow{Cl} RCl + H_2O$