Zn(s) + Cl2 (1 atm) arrow Zn2+ + 2 Cl- ; E° = 2.0 V To increase the e.m.f. of the above cell

Question

Zn(s) + Cl2 (1 atm) arrow Zn2+ + 2 Cl- ; E° = 2.0 V To increase the e.m.f. of the above cell (A) [Zn2+] should be increased (B) [Zn2+] should be decreased (C) [Cl-] should be increased (D) partial pressure of Cl2 should be decreased.

Tardigrade Admin · Accepted Answer

Ecell = E°cell - (0.0591/2) log [Zn2+][Cl-]2 Hence, decrease in [Zn2+] will increase Ecell

Q. $Z n_{(s)} + C l_{2} (1 a t m) \to Z n^{2 +} + 2 C l^{-}; E^{\circ} = 2.0 V$ To increase the e.m.f. of the above cell

$[Z n^{2 +}]$ should be increased

$[Z n^{2 +}]$ should be decreased

$[C l^{-}]$ should be increased

partial pressure of $C l_{2}$ should be decreased.

$E_{ce ll} = E_{ce ll}^{\circ} - \frac{0.0591}{2} lo g [Z n^{2 +}] [C l^{-}]^{2}$
Hence, decrease in $[Z n^{2 +}]$ will increase $E_{ce ll}$

Q. Zn(s)​+Cl2​(1atm)→Zn2++2Cl−;E∘=2.0V To increase the e.m.f. of the above cell

[Zn2+] should be increased

[Zn2+] should be decreased

[Cl−] should be increased

partial pressure of Cl2​ should be decreased.