Zinc sulphate contains 22.65 % of zinc and 43.9 % of water of crystallization. If the law of constant proportions is true, then the weight of zinc required to produce 20 g of the crystals will be

Question

Zinc sulphate contains 22.65 % of zinc and 43.9 % of water of crystallization. If the law of constant proportions is true, then the weight of zinc required to produce 20 g of the crystals will be (A) 45.3 g (B) 4.53 g (C) 0.453 g (D) 453 g

Tardigrade Admin · Accepted Answer

100 g of ZnSO4 crystals are obtained from = 22.65 g Zn 1 g of ZnSO4 crystals will be obtained from =(22.65/100)g Zn 20 g of ZnSO4 crystals obtained from =(22.65/100)×20=4.53g

Q. Zinc sulphate contains $22.65%$ of zinc and $43.9%$ of water of crystallization. If the law of constant proportions is true, then the weight of zinc required to produce $20 g$ of the crystals will be

$45.3 g$

$4.53 g$

$0.453 g$

$453 g$

$100 g o f Z n S O_{4}$ crystals are obtained from $= 22.65 g Z n$
$1 g o f Z n S O_{4}$ crystals will be obtained from $= \frac{22.65}{100} g Z n$
$20 g o f Z n S O_{4}$ crystals obtained from $= \frac{22.65}{100} \times 20 = 4.53 g$

Q. Zinc sulphate contains 22.65% of zinc and 43.9% of water of crystallization. If the law of constant proportions is true, then the weight of zinc required to produce 20g of the crystals will be

45.3g

4.53g

0.453g

453g