Zinc reacts with hydrochloric acid to give hydrogen and zinc chloride. The volume of hydrogen gas produced at STP from the reaction of 11.5 g of zine with excess HCl is L (Nearest integer) (Given: Molar mass of Zn is 65.4 g mol -1 and Molar volume of H 2 at STP =22.7 L )

Question

Zinc reacts with hydrochloric acid to give hydrogen and zinc chloride. The volume of hydrogen gas produced at STP from the reaction of 11.5 g of zine with excess HCl is L (Nearest integer) (Given: Molar mass of Zn is 65.4 g mol -1 and Molar volume of H 2 at STP =22.7 L ) (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

Zn +2 HCl arrow ZnCl 2+ H 2 uparrow text Moles of Zn text used =(11.5/65.4)= text Moles of H 2 text evolved text Volume of H 2=(11.5/65.4) × 22.7 L =3.99 L =4

Q. Zinc reacts with hydrochloric acid to give hydrogen and zinc chloride. The volume of hydrogen gas produced at STP from the reaction of 11.5g of zine with excess HCl is ___L (Nearest integer) (Given: Molar mass of Zn is 65.4gmol−1 and Molar volume of H2​ at STP=22.7L )

Zn+2HCl→ZnCl2​+H2​↑ Moles of Zn used =65.411.5​= Moles of H2​ evolved Volume of H2​=65.411.5​×22.7L=3.99L =4

$Z n + 2 H Cl \to Z n C l_{2} + H_{2} ↑$
$Moles of Z n used = \frac{11.5}{65.4} = Moles of H_{2} evolved$
$Volume of H_{2} = \frac{11.5}{65.4} \times 22.7 L = 3.99 L$
$= 4$