Zinc and hydrochloric acid react according to the following reaction: Zn(s)+ 2HCl (a q .) arrow ZnCl2(.aq..)+H2(.g.) If 0.30 mole of Zn is added to 0.52 mole HCl, how many moles of H2 is produced?

Question

Zinc and hydrochloric acid react according to the following reaction: Zn(s)+ 2HCl (a q .) arrow ZnCl2(.aq..)+H2(.g.) If 0.30 mole of Zn is added to 0.52 mole HCl, how many moles of H2 is produced? (A) 0.2 (B) 0.62 (C) 0.6 (D) 0.26

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="Solution" src="https://cdn.tardigrade.in/q/nta/c-7wq6sji1tmcg.png" /> ∵ Mole ratio of Zn:HCl:H2 is 1:2:1 2 textmole textHCl textgives = 1 textmole textH text2 0.52 textmole textHCl textgives=(1 × 0.52/2)=0.26 textmole Note that HCl is used completely and thus it is limiting reagent.

Q. Zinc and hydrochloric acid react according to the following reaction :

$Z n (s) + 2 H Cl (a q .) \to Z n C l_{2} (a q .) + H_{2} (g)$

If $0.30 m o l e o f Z ni s$ added to $0.52 m o l e H Cl,$ how many moles of $H_{2}$ is produced?

$0.2$

$0.62$

$0.6$

$0.26$

$∵ M o l e r a t i o o f Z n : H Cl : H_{2} i s 1 : 2 : 1$

$2 mole HCl gives = 1 mole H_{2}$

$0.52 mole HCl gives = \frac{1 \times 0.52}{2} = 0.26 mole$

Note that $H Cl$ is used completely and thus it is limiting reagent.

Q. Zinc and hydrochloric acid react according to the following reaction : Zn(s)+2HCl(aq.)→ZnCl2​(aq.)+H2​(g) If 0.30moleofZnis added to 0.52moleHCl, how many moles of H2​ is produced?

0.2

0.62

0.6

0.26