Y g of non-volatile organic substance of molecular mass M is dissolved in 250 g benzene. Molal elevation constant of benzene is Kb. Elevation in its boiling point.is given by

Question

Y g of non-volatile organic substance of molecular mass M is dissolved in 250 g benzene. Molal elevation constant of benzene is Kb. Elevation in its boiling point.is given by (A) (M/Kb Y) (B) (4 Kb Y/M) (C) (Kb Y/4 M) (D) (Kb Y/M)

Tardigrade Admin · Accepted Answer

Δ Tb=(1000 × Kb × Y/250 × M)=(4 Kb Y/M)

Q. $Y g$ of non-volatile organic substance of molecular mass $M$ is dissolved in $250 g$ benzene. Molal elevation constant of benzene is $K_{b}$ . Elevation in its boiling point.is given by

$\frac{M}{K _{b} Y}$

$\frac{4 K _{b} Y}{M}$

$\frac{K _{b} Y}{4 M}$

$\frac{K _{b} Y}{M}$

$Δ T_{b} = \frac{1000 \times K _{b} \times Y}{250 \times M} = \frac{4 K _{b} Y}{M}$

Q. Yg of non-volatile organic substance of molecular mass M is dissolved in 250g benzene. Molal elevation constant of benzene is Kb​. Elevation in its boiling point.is given by

Kb​YM​

M4Kb​Y​

4MKb​Y​

MKb​Y​