y component of velocity is 20 and x component of velocity is 10. The direction of motion of the body with the horizontal at this instant is :

Question

y component of velocity is 20 and x component of velocity is 10. The direction of motion of the body with the horizontal at this instant is : (A)  tan -1(2)  (B)  tan -1(1/2)  (C)  450  (D)  0°

Tardigrade Admin · Accepted Answer

According to the condition of question tan θ =( upsilon y/ upsilon x)=(20/10)=2 ∴ θ = tan -1(2)

Q. y component of velocity is 20 and x component of velocity is 10. The direction of motion of the body with the horizontal at this instant is :

$tan^{- 1} (2)$

$tan^{- 1} (1/2)$

$45^{0}$

$0^{\circ}$

According to the condition of question $tan θ = \frac{υ _{y}}{υ _{x}} = \frac{20}{10} = 2$ $∴$ $θ = tan^{- 1} (2)$

Q. y component of velocity is 20 and x component of velocity is 10. The direction of motion of the body with the horizontal at this instant is :

tan−1(2)

tan−1(1/2)

450

0∘

According to the condition of question tanθ=υx​υy​​=1020​=2 ∴ θ=tan−1(2)

$tan^{- 1} (2)$

$tan^{- 1} (1/2)$

$45^{0}$

$0^{\circ}$

According to the condition of question $tan θ = \frac{υ _{y}}{υ _{x}} = \frac{20}{10} = 2$ $∴$ $θ = tan^{- 1} (2)$