Question

$Xe{O}_4$ molecule is tetrahedral having ‘n’ number of $p\pi -d\pi$ bonds. The value of ‘n’ is

• A. 1
• B. 2
• C. 3
• D. 4

Answer 1

Answer: (D)

Xenon undergoes $s{p}^3$ hybridization

In the fourth excited state xenon atom, has 8 unpaired electrons

One $\text{s}$ and three $\text{p}$ orbital undergo ${\text{sp}}^{\text{3}}$ hybridization. Four $s{p}^3$ hybrid orbitals form four σ bonds with oxygen atoms. They are $\text{σ}{\text{sp}}^{\text{3}}-\text{p}$ . Four pπ - dπ bonds are also formed with oxygen atoms by the unpaired electrons.