Xenon crystallizes in face-centered cubic lattice, and the edge of the unit cell is 620 pm. The radius of a xenon atom is

Question

Xenon crystallizes in face-centered cubic lattice, and the edge of the unit cell is 620 pm. The radius of a xenon atom is (A) 438.5 pm (B) 219.20 pm (C) 536.94 pm (D) 265.5 pm

Tardigrade Admin · Accepted Answer

For an fcc lattice, 4 r=√2 a, where a=620 pm r=(√2/4) ⋅ a=(1/2 √2) ⋅ a=(1/2 √2) ⋅ 620=219.20 pm

Q. Xenon crystallizes in face-centered cubic lattice, and the edge of the unit cell is $620 p m$ . The radius of a xenon atom is

438.5 pm

219.20 pm

536.94 pm

265.5 pm

For an fcc lattice, $4 r = 2 a$ , where $a = 620 p m$

$r = \frac{2}{4} \cdot a = \frac{1}{2 2} \cdot a = \frac{1}{2 2} \cdot 620 = 219.20 p m$

Q. Xenon crystallizes in face-centered cubic lattice, and the edge of the unit cell is 620pm. The radius of a xenon atom is