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Tardigrade
Question
Chemistry
XeF4 reacts with SbF5 to form [XeFx]+ [SbFy]-. The value of 'Y' is.
Q.
X
e
F
4
reacts with
S
b
F
5
to form
[
X
e
F
x
]
+
[
S
b
F
y
]
−
.
The value of
′
Y
′
is____.
126
162
NTA Abhyas
NTA Abhyas 2022
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Answer:
6
Solution:
X
e
F
4
+
S
b
F
5
→
[
X
e
F
3
]
+
[
S
b
F
6
]
−
Hence, the values of
X
and
Y
are
3
and
6
,
respectively.