Xe react directly with F2 in different conditions by volume. Ratio of Xe and F2 is given to make different Xenon fluoride products. XeF2⇒ Xe:F2=x:a=1:0.5 XeF4⇒ Xe:F2=x:b XeF6⇒ Xe:F2=x:c The value of a+b+c will be Round off your answer to the nearest integer after multiplying with 10.

Question

Xe react directly with F2 in different conditions by volume. Ratio of Xe and F2 is given to make different Xenon fluoride products. XeF2⇒ Xe:F2=x:a=1:0.5 XeF4⇒ Xe:F2=x:b XeF6⇒ Xe:F2=x:c The value of a+b+c will be Round off your answer to the nearest integer after multiplying with 10. (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

For XeF 2 ⇒ Xe 2 F 2=1: 0.50 For XeF 4 ⇒ Xe: F 2=1: 5 For XeF 6 ⇒ Xe: F 2=1: 20 Sum =20+5+0.50=25.50

For XeF2​⇒Xe2​F2​=1:0.50 For XeF4​⇒Xe:F2​=1:5 For XeF6​⇒Xe:F2​=1:20 Sum =20+5+0.50=25.50

For $X e F_{2} \Rightarrow X e_{2} F_{2} = 1 : 0.50$
For $X e F_{4} \Rightarrow X e : F_{2} = 1 : 5$
For $X e F_{6} \Rightarrow X e : F_{2} = 1 : 20$
Sum $= 20 + 5 + 0.50 = 25.50$