XCl2( textexcess)+YCl2 arrow XCl4+Y downarrow YO xrightarrow [ 400o C]Δ (1/2)O2+Y , Ore of Y would be

Question

XCl2( textexcess)+YCl2 arrow XCl4+Y downarrow YO xrightarrow [> 400o C]Δ (1/2)O2+Y , Ore of Y would be (A) Siderite (B) Cinnabar (C) Malachite (D) Hornsilver

Tardigrade Admin · Accepted Answer

The reaction sequence is as follows underset(XCl2)SnCl 2+ underset(YCl2)HgCl 2 arrow underset(XCl4)SnCl 4+ underset (Y) Hg HgO xrightarrow[> 400° C ] Δ Hg + (1/2)O2 HgS arrow Cinnabar

Q. $XC l_{2} (excess) + Y C l_{2} \to XC l_{4} + Y ↓$
$Y O Δ > 40 0^{o} C \frac{1}{2} O_{2} + Y$ , Ore of $Y$ would be

Siderite

Cinnabar

Malachite

Hornsilver

The reaction sequence is as follows
$(XC l_{2}) S n C l_{2} + (Y C l_{2}) H g C l_{2} \to (XC l_{4}) S n C l_{4} + (Y) H g$
$H g O Δ > 40 0^{\circ} C H g + \frac{1}{2} O_{2}$
$H g S \to$ Cinnabar

Q. XCl2​(excess)+YCl2​→XCl4​+Y↓ YOΔ>400oC​21​O2​+Y , Ore of Y would be