Question

$XCl_{2}\left(\text{excess}\right)+YCl_{2} \rightarrow XCl_{4}+Y\downarrow$
$YO \xrightarrow [> 400^{o} C]{\Delta }\frac{1}{2}O_{2}+Y$ , Ore of $Y$ would be

• A. Siderite
• B. Cinnabar
• C. Malachite
• D. Hornsilver

Answer 1

Answer: (B)

The reaction sequence is as follows
$\underset{(XCl_2)}{SnCl _2}+ \underset{(YCl_2)}{HgCl _2} \rightarrow \underset{(XCl_4)}{SnCl _4}+\underset{ (Y)}{ Hg }$
$HgO \xrightarrow[> 400^{\circ} C ]{ \Delta} Hg + \frac{1}{2}O_2$
$HgS \rightarrow$ Cinnabar