Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Chemistry
X reacts with aqueous NaOH solution to form Y and H 2 Aqueous solution of Y is heated to 323-333 K and on passing CO 2 into it, Na 2 CO 3 and Z are formed. When Z is heated to 1200° C , Al 2 O 3 is formed. X, Y and Z respectively are
Q.
X
reacts with aqueous
N
a
O
H
solution to form
Y
and
H
2
Aqueous solution of
Y
is heated to
323
−
333
K
and on passing
C
O
2
into it,
N
a
2
C
O
3
and
Z
are formed. When
Z
is heated to
120
0
∘
C
,
A
l
2
O
3
is formed.
X
,
Y
and
Z
respectively are
2027
233
The p-Block Elements
Report Error
A
A
l
,
A
lC
l
3
,
N
a
A
l
O
2
0%
B
Z
n
,
N
a
2
Z
n
O
2
,
A
l
(
O
H
)
3
100%
C
A
l
,
A
l
(
O
H
)
3
,
A
lC
l
3
0%
D
A
l
,
N
a
A
l
O
2
,
A
l
(
O
H
)
3
0%
Solution:
(
X
)
2
A
l
+
2
N
a
O
H
+
2
H
2
O
→
(
Y
)
2
N
a
A
l
O
2
+
3
H
2
(
Y
)
2
N
a
A
l
O
2
+
C
O
2
+
3
H
2
O
(
Z
)
⟶
Δ
2
A
l
(
O
H
)
3
+
N
a
2
C
O
3
(
Z
)
2
A
l
(
O
H
)
3
⟶
120
0
∘
C
A
l
2
O
3
+
3
H
2
O