Question

$x$ mole of $BaC{O}_3$ are soluble in $1L$ then $x$ is related to its solubility product by the expression

• A. $x=K_{sp}$
• B. $x^2=\sqrt{K_{sp}}$
• C. $x=\sqrt{K_{sp}}$
• D. $x=\frac{K_{sp}}{2}$

Answer 1

Answer: (C)

$BaC{O}_3\to B{a}^{2+}+C{O}_3^{2-}$
If solubility $=x$, then
$K_{sp}=x^2$
$x=\sqrt{K_{sp}}$