Question

$x\in R:\frac{2x-1}{x^3+4x^2+3x}\in R$ Equals

• A. R - {0}
• B. R- {0,1,3}
• C. R-{0, -1,-3}
• D. R- 0,-1,-3,+ $\frac{1}{2}$

Answer 1

Answer: (C)

Let $A=x\in R:\frac{2x-1}{x^3+4x^2+3x}$
Now , $x^3+4x^2+3x=x(x^2+4x+3)$
$=x(x+3)(x+1)$
$A=R-\{0,-1,-3\}$