'x' grams of calcium carbonate was completely burnt in air. The weight of the solid residue formed is 28 g . What is the value of 'x' in grams ?

Question

'x' grams of calcium carbonate was completely burnt in air. The weight of the solid residue formed is 28 g . What is the value of 'x' in grams ? (A) 44 (B) 200 (C) 150 (D) 50

Tardigrade Admin · Accepted Answer

underset text1 molCaCO 3 xrightarrowΔ underset text1 mol CaO + CO 2 =100 g =40+16 =56 g To produce 56 g of residue (CaO), CaCO3 needed =100 g ∴ To produce 28 g of residue, CaCO3 needed =(100/56)×28 =50 g

Q. ' $x$ ' grams of calcium carbonate was completely burnt in air. The weight of the solid residue formed is $28 g$ . What is the value of ' $x$ ' in grams ?

44

200

150

50

$1 mol C a C O_{3} Δ 1 mol C a O + C O_{2}$
$= 100 g = 40 + 16$
$= 56 g$
To produce $56 g$ of residue $(C a O)$ , $C a C O_{3}$ needed
$= 100 g$
$∴$ To produce $28 g$ of residue, $C a C O_{3}$ needed
$= \frac{100}{56} \times 28$
$= 50 g$

Q. 'x' grams of calcium carbonate was completely burnt in air. The weight of the solid residue formed is 28g . What is the value of 'x' in grams ?

44

200

150

50

1 molCaCO3​​Δ​1 mol CaO​+CO2​ =100g=40+16 =56g To produce 56g of residue (CaO), CaCO3​ needed =100g ∴ To produce 28g of residue, CaCO3​ needed =56100​×28 =50g

Q. ' $x$ ' grams of calcium carbonate was completely burnt in air. The weight of the solid residue formed is $28 g$ . What is the value of ' $x$ ' in grams ?

$1 mol C a C O_{3} Δ 1 mol C a O + C O_{2}$
$= 100 g = 40 + 16$
$= 56 g$
To produce $56 g$ of residue $(C a O)$ , $C a C O_{3}$ needed
$= 100 g$
$∴$ To produce $28 g$ of residue, $C a C O_{3}$ needed
$= \frac{100}{56} \times 28$
$= 50 g$