Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Chemistry
X and Y in the below reaction are ......... and .......... respectively C6H5 - CO2H + X ->[ textheat] C6H5 - COCl ->[H2,Pd/BaSO4][ textQuinoline]
Q.
X
and
Y
in the below reaction are ......... and .......... respectively
C
6
H
5
−
C
O
2
H
+
X
heat
C
6
H
5
−
COCl
H
2
,
Pd/BaS
O
4
Quinoline
1924
223
KEAM
KEAM 2017
Report Error
A
SOC
l
2
and
C
6
H
5
C
H
O
0%
B
(
COCl
)
2
and
C
6
H
5
C
H
3
0%
C
SOC
l
2
and
C
6
H
5
C
H
3
100%
D
(
COCl
)
2
and
C
6
H
5
C
H
2
O
H
0%
E
SOC
l
2
and
C
6
H
5
C
H
2
Cl
0%
Solution:
C
6
H
5
C
O
2
H
+
(
X
)
SOC
l
2
⟶
C
6
H
5
−
COCl
+
H
2
,
Pd/BaS
O
4
Quinoline
(
Y
)
(Roseumund reduction)
C
6
H
5
C
H
O
∴
(
X
)
and
(
Y
)
are
SOC
l
2
and
C
6
H
5
C
H
O
respectively.