Write the set builder form A = -1, 1

Question

Write the set builder form A = -1, 1 (A) A = x: x is a real number (B) A = (x: x is an integer) (C) A = x: x is a root of the equation x2 = 1 (D) A = x: x is a root of the equation x2 + 1 = 0

Tardigrade Admin · Accepted Answer

-1,1 are the roots of the equation x2-1=0 Hence, set builder form of A can be written as A= x: x. is a root of the equation .x2=1

Q. Write the set builder form $A = - 1, 1$

A = {x : x is a real number}

A = (x : x is an integer)

A = {x : x is a root of the equation $x^{2}$ = 1}

A = {x : x is a root of the equation $x^{2}$ + 1 = 0}

$- 1, 1$ are the roots of the equation $x^{2} - 1 = 0$ Hence, set builder form of $A$ can be written as $A = {x : x$ is a root of the equation $x^{2} = 1}$

Q. Write the set builder form A=−1,1

A = {x : x is a real number}

A = (x : x is an integer)

A = {x : x is a root of the equation x2 = 1}

A = {x : x is a root of the equation x2 + 1 = 0}

−1,1 are the roots of the equation x2−1=0 Hence, set builder form of A can be written as A={x:x is a root of the equation x2=1}

Q. Write the set builder form $A = - 1, 1$

A = {x : x is a root of the equation $x^{2}$ = 1}

A = {x : x is a root of the equation $x^{2}$ + 1 = 0}

$- 1, 1$ are the roots of the equation $x^{2} - 1 = 0$ Hence, set builder form of $A$ can be written as $A = {x : x$ is a root of the equation $x^{2} = 1}$