Question

Write the product:
$\stackrel{\underset{|}{C{H}_{2}OH}}{C{H}_{2}OH}\stackrel{\mathrm{HI}{\mathrm{O}}_4}{\to }$

• A. formaldehyde
• B. acetaldehyde
• C. formic acid
• D. acetic acid

Answer 1

Answer: (A)

Key Idea: Oxidative cleavage takes place when polyhydric alcohols are treated with $HI{O}_4$
$\stackrel{\underset{|}{C{H}_{2}OH}}{C{H}_{2}OH}\stackrel{\mathrm{HI}{\mathrm{O}}_4}{\to }2HCHO.$