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Q. Write the product:
$\overset{\underset{|}{CH_{2}OH}}{CH_{2}OH} \ce{->[{HIO_{4}}]}$

Bihar CECEBihar CECE 2002

Solution:

Key Idea: Oxidative cleavage takes place when polyhydric alcohols are treated with $ HIO_{4} $
$\overset{\underset{|}{CH_{2}OH}}{CH_{2}OH} \ce{->[{HIO_{4}}]} 2HCHO. $