Question

Work done per mol in an isothermal change is

• A. $RT{\log }_{10}\frac{V_2}{V_1}$
• B. $RT{\log }_{10}\frac{V_1}{V_2}$
• C. $RT{\log }_e\frac{V_2}{V_1}$
• D. $RT{\log }_e\frac{V_1}{V_2}$

Answer 1

Answer: (C)

For isothermal process $pV=RT\Rightarrow p=\frac{RT}{V}$ $\therefore$ $W=pdV={\int }_{V_1}^{V_2}\frac{RT}{V}dV=RT{\log }_e\frac{V_2}{V_1}$