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Physics
Work done per mol in an isothermal change is
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Q. Work done per mol in an isothermal change is
CMC Medical
CMC Medical 2009
A
$ RT{{\log }_{10}}\frac{{{V}_{2}}}{{{V}_{1}}} $
B
$ RT{{\log }_{10}}\frac{{{V}_{1}}}{{{V}_{2}}} $
C
$ RT{{\log }_{e}}\frac{{{V}_{2}}}{{{V}_{1}}} $
D
$ RT{{\log }_{e}}\frac{{{V}_{1}}}{{{V}_{2}}} $
Solution:
For isothermal process $ pV=RT\Rightarrow p=\frac{RT}{V} $ $ \therefore $ $ W=pdV=\int_{{{V}_{1}}}^{{{V}_{2}}}{\frac{RT}{V}}dV=RT{{\log }_{e}}\frac{{{V}_{2}}}{{{V}_{1}}} $