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Tardigrade
Question
Physics
Work done per mol in an isothermal change is
Q. Work done per mol in an isothermal change is
2467
205
Thermodynamics
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A
RT
lo
g
10
V
1
V
2
22%
B
RT
lo
g
10
V
2
V
1
6%
C
RT
lo
g
e
V
1
V
2
61%
D
RT
lo
g
e
V
2
V
1
12%
Solution:
For isothermal process
p
V
=
RT
⇒
p
=
V
RT
=
W
=
p
d
V
=
∫
v
1
v
2
V
RT
d
V
=
RT
lo
g
e
V
1
V
2