With six cards, each containing one letter, one forms the word "LATENT". The cards are then shuffled, and at random cards are drawn one at a time. The probability that the arrangement of letters will form the word "TALENT" is

Question

With six cards, each containing one letter, one forms the word "LATENT". The cards are then shuffled, and at random cards are drawn one at a time. The probability that the arrangement of letters will form the word "TALENT" is (A) (1/120) (B) (1/360) (C) (1/420) (D) (1/720)

Tardigrade Admin · Accepted Answer

n ( S )=(6 !/2 !)=360 n(A)=1 ⇒ P(A)=(1/360) ⇒ B

Q. With six cards, each containing one letter, one forms the word "LATENT". The cards are then shuffled, and at random cards are drawn one at a time. The probability that the arrangement of letters will form the word "TALENT" is

$\frac{1}{120}$

$\frac{1}{360}$

$\frac{1}{420}$

$\frac{1}{720}$

$n (S) = \frac{6 !}{2 !} = 360$
$n (A) = 1 \Rightarrow P (A) = \frac{1}{360} \Rightarrow B$

Q. With six cards, each containing one letter, one forms the word "LATENT". The cards are then shuffled, and at random cards are drawn one at a time. The probability that the arrangement of letters will form the word "TALENT" is

1201​

3601​

4201​

7201​

n(S)=2!6!​=360 n(A)=1⇒P(A)=3601​⇒B

$\frac{1}{120}$

$\frac{1}{360}$

$\frac{1}{420}$

$\frac{1}{720}$

$n (S) = \frac{6 !}{2 !} = 360$
$n (A) = 1 \Rightarrow P (A) = \frac{1}{360} \Rightarrow B$