With increase in frequency of an a.c. supply, the impedance of an LCR series circuit

Question

With increase in frequency of an a.c. supply, the impedance of an LCR series circuit (A) Remains constant (B) Decreases (C) Increases (D) Decreases at first, becomes minimum and then increases

Tardigrade Admin · Accepted Answer

XL=2 π f L, Xc=(1/2 π f C) When f is increased, XL will increase ,XC will decrease So XL-XC will increase, hence z will increase

Q. With increase in frequency of an a.c. supply, the impedance of an LCR series circuit

Remains constant

Decreases

Increases

Decreases at first, becomes minimum and then increases

$X_{L} = 2 π f L,$
$X_{c} = \frac{1}{2 π f C}$
When $f$ is increased, $X_{L}$ will increase
, $X_{C}$ will decrease
So $X_{L} - X_{C}$ will increase, hence $z$ will increase

Q. With increase in frequency of an a.c. supply, the impedance of an LCR series circuit

Remains constant

Decreases

Increases

Decreases at first, becomes minimum and then increases

XL​=2πfL, Xc​=2πfC1​ When f is increased, XL​ will increase ,XC​ will decrease So XL​−XC​ will increase, hence z will increase

$X_{L} = 2 π f L,$
$X_{c} = \frac{1}{2 π f C}$
When $f$ is increased, $X_{L}$ will increase
, $X_{C}$ will decrease
So $X_{L} - X_{C}$ will increase, hence $z$ will increase