With a monochromatic light, the fringe-width obtained in a Young's double slit experiment is 0.133 cm. The whole setup is immersed in water of refractive index 1.33, then the new fringe-width is

Question

With a monochromatic light, the fringe-width obtained in a Young's double slit experiment is 0.133 cm. The whole setup is immersed in water of refractive index 1.33, then the new fringe-width is (A) 0.133 m (B) 0.1 cm (C) 1.33 × 1.33 cm (D) (1.33/2) cm

Tardigrade Admin · Accepted Answer

β prime=(β/μ)=(0.133/1.33)=0.1 cm

Q. With a monochromatic light, the fringe-width obtained in a Young's double slit experiment is $0.133 c m$ . The whole setup is immersed in water of refractive index $1.33$ , then the new fringe-width is

$0.133 m$

$0.1 c m$

$1.33 \times 1.33 c m$

$\frac{1.33}{2} c m$

$β^{'} = \frac{β}{μ} = \frac{0.133}{1.33} = 0.1 c m$

Q. With a monochromatic light, the fringe-width obtained in a Young's double slit experiment is 0.133cm. The whole setup is immersed in water of refractive index 1.33, then the new fringe-width is

0.133m

0.1cm

1.33×1.33cm

21.33​cm