Q.
Which term of the sequence {9−8i,8−6i,7−4i,....} is a real number?
1508
213
J & K CETJ & K CET 2017Sequences and Series
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Solution:
We have an A.P. {9−8i,8−6i,−4i,…}
Here, first term, a=9−8i
And common difference, d=8−6i−9+8i =−1+2i
Let rth term be real number. Tr=a+(r−1)d=9−8i+(r−1)(−1+2i) =9−8i−r+1+2ir−2i =10−r+i(2r−10)
since, Tr is real, ∴2r−10=0 ⇒r=5
Thus, 5th term is a real number