Which statement is wrong about the hydrolysis of R- overset⊕N ≡ oversetΘC ?

Question

Which statement is wrong about the hydrolysis of R- overset⊕N ≡ oversetΘC ? (A) Isocyanides are hydrolysed with aqueous dilute acids but not by alkali. (B) In the hydrolysis of (R- overset⊕N ≡ oversetΘC), first electrophile (H⊕) add on the C atom and then nucleophile ( oversetΘOH) adds to the same C atom. (C) On partial hydrolysis, (RNC) gives N-substituted methanamide or formamide. (D) On complete hydrolysis, (RNC) gives 1° amine and RCOOH.

Tardigrade Admin · Accepted Answer

Correct answer is (b) In the hydrolysis of (R- overset⊕N ≡ oversetΘC), first electrophile (H⊕) add on the C atom and then nucleophile ( oversetΘOH) adds to the same C atom.

Q. Which statement is wrong about the hydrolysis of $R - N \oplus \equiv C Θ$ ?

Isocyanides are hydrolysed with aqueous dilute acids but not by alkali.

In the hydrolysis of $(R - N \oplus \equiv C Θ)$ , first electrophile $(H^{\oplus})$ add on the $C$ atom and then nucleophile $(O Θ H)$ adds to the same $C$ atom.

On partial hydrolysis, (RNC) gives $N$ -substituted methanamide or formamide.

On complete hydrolysis, (RNC) gives $1^{\circ}$ amine and $RCOO H$ .

Correct answer is (b) In the hydrolysis of $(R - N \oplus \equiv C Θ)$ , first electrophile $(H^{\oplus})$ add on the $C$ atom and then nucleophile $(O Θ H)$ adds to the same $C$ atom.

Q. Which statement is wrong about the hydrolysis of R−N⊕≡CΘ ?

Isocyanides are hydrolysed with aqueous dilute acids but not by alkali.

In the hydrolysis of (R−N⊕≡CΘ), first electrophile (H⊕) add on the C atom and then nucleophile (OΘH) adds to the same C atom.

On partial hydrolysis, (RNC) gives N-substituted methanamide or formamide.

On complete hydrolysis, (RNC) gives 1∘ amine and RCOOH.

Correct answer is (b) In the hydrolysis of (R−N⊕≡CΘ), first electrophile (H⊕) add on the C atom and then nucleophile (OΘH) adds to the same C atom.

Q. Which statement is wrong about the hydrolysis of $R - N \oplus \equiv C Θ$ ?

In the hydrolysis of $(R - N \oplus \equiv C Θ)$ , first electrophile $(H^{\oplus})$ add on the $C$ atom and then nucleophile $(O Θ H)$ adds to the same $C$ atom.

On partial hydrolysis, (RNC) gives $N$ -substituted methanamide or formamide.

On complete hydrolysis, (RNC) gives $1^{\circ}$ amine and $RCOO H$ .

Correct answer is (b) In the hydrolysis of $(R - N \oplus \equiv C Θ)$ , first electrophile $(H^{\oplus})$ add on the $C$ atom and then nucleophile $(O Θ H)$ adds to the same $C$ atom.