Which reaction is not feasible?

Question

Which reaction is not feasible? (A) 2KI + Br2 arrow 2KBr + I2 (B) 2KBr + I2 arrow 2KI + Br2 (C) 2KBr +Cl2 arrow 2KCl + Br2 (D) 2H2O+ 2F2 arrow 4HF +O2

Tardigrade Admin · Accepted Answer

2KBr + I2 2KI + Br2 reaction is not possible because Br- ion is not oxidised in Br2 with I2 due to higher electrode (oxidation) potential of I2 than bromine.

Q. Which reaction is not feasible?

$2 K I + B r_{2} \to 2 K B r + I_{2}$

$2 K B r + I_{2} \to 2 K I + B r_{2}$

$2 K B r + C l_{2} \to 2 K Cl + B r_{2}$

$2 H_{2} O + 2 F_{2} \to 4 H F + O_{2}$

$2 K B r + I_{2} 2 K I + B r_{2}$ reaction is not possible because $B r^{-}$ ion is not oxidised in $B r_{2}$ with $I_{2}$ due to higher electrode (oxidation) potential of $I_{2}$ than bromine.

Q. Which reaction is not feasible?

2KI+Br2​→2KBr+I2​

2KBr+I2​→2KI+Br2​

2KBr+Cl2​→2KCl+Br2​

2H2​O+2F2​→4HF+O2​

2KBr+I2​2KI+Br2​ reaction is not possible because Br− ion is not oxidised in Br2​ with I2​ due to higher electrode (oxidation) potential of I2​ than bromine.

$2 K I + B r_{2} \to 2 K B r + I_{2}$

$2 K B r + I_{2} \to 2 K I + B r_{2}$

$2 K B r + C l_{2} \to 2 K Cl + B r_{2}$

$2 H_{2} O + 2 F_{2} \to 4 H F + O_{2}$

$2 K B r + I_{2} 2 K I + B r_{2}$ reaction is not possible because $B r^{-}$ ion is not oxidised in $B r_{2}$ with $I_{2}$ due to higher electrode (oxidation) potential of $I_{2}$ than bromine.