Which particle among the following will have the smallest de-Broglie wavelength, assuming that they have the same velocity?

Question

Which particle among the following will have the smallest de-Broglie wavelength, assuming that they have the same velocity? (A) A positron (B) A photon (C) An a-particle (D) A neutron

Tardigrade Admin · Accepted Answer

The de-Broglie equation is λ =(h/p)=(h/mv) Here, h and v are constant. So, λ propto (1/m) . Since, the a-particle has the highest mass among the given entities, it has the smallest de-Broglie wavelength.

Q. Which particle among the following will have the smallest de-Broglie wavelength, assuming that they have the same velocity?

A positron

A photon

An a-particle

A neutron

The de-Broglie equation is $λ = \frac{h}{p} = \frac{h}{m v}$ Here, h and v are constant. So, $λ \propto \frac{1}{m}$ . Since, the a-particle has the highest mass among the given entities, it has the smallest de-Broglie wavelength.

Q. Which particle among the following will have the smallest de-Broglie wavelength, assuming that they have the same velocity?

A positron

A photon

An a-particle

A neutron

The de-Broglie equation is λ=ph​=mvh​ Here, h and v are constant. So, λ∝m1​ . Since, the a-particle has the highest mass among the given entities, it has the smallest de-Broglie wavelength.

The de-Broglie equation is $λ = \frac{h}{p} = \frac{h}{m v}$ Here, h and v are constant. So, $λ \propto \frac{1}{m}$ . Since, the a-particle has the highest mass among the given entities, it has the smallest de-Broglie wavelength.