Which pair of the gaseous species diffuse through a small jet with the same rate of diffusion at same P and T :-

Question

Which pair of the gaseous species diffuse through a small jet with the same rate of diffusion at same P and T :- (A) NO,CO (B) NO,CO2 (C) NH3,PH3 (D) NO,C2H6

Tardigrade Admin · Accepted Answer

Graham's law states that the rate of diffusion or of effusion of a gas is inversely proportional to the square root of its molecular weight. (r1/r2)=√(M2/M1) M1=M2

Q. Which pair of the gaseous species diffuse through a small jet with the same rate of diffusion at same $P$ and $T$ :-

$NO, CO$

$NO, C O_{2}$

$N H_{3}, P H_{3}$

$NO, C_{2} H_{6}$

Graham's law states that the rate of diffusion or of effusion of a gas is inversely proportional to the square root of its molecular weight.
$\frac{r _{1}}{r _{2}} = \frac{M _{2}}{M _{1}}$
$M_{1} = M_{2}$

Q. Which pair of the gaseous species diffuse through a small jet with the same rate of diffusion at same P and T :-

NO,CO

NO,CO2​

NH3​,PH3​

NO,C2​H6​

Graham's law states that the rate of diffusion or of effusion of a gas is inversely proportional to the square root of its molecular weight. r2​r1​​=M1​M2​​​ M1​=M2​

Q. Which pair of the gaseous species diffuse through a small jet with the same rate of diffusion at same $P$ and $T$ :-

$NO, CO$

$NO, C O_{2}$

$N H_{3}, P H_{3}$

$NO, C_{2} H_{6}$

Graham's law states that the rate of diffusion or of effusion of a gas is inversely proportional to the square root of its molecular weight.
$\frac{r _{1}}{r _{2}} = \frac{M _{2}}{M _{1}}$
$M_{1} = M_{2}$