Question

Which one of the followings has maximum number of atoms ?

• A. 1g of Ag(s) [Atomic mass of Ag = 108]
• B. 1g of Mg(s) [Atomic mass of Mg = 24]
• C. 1g of $O_2(g)$ [Atomic mass of O = 16]
• D. 1g of $Li(s)$ [Atomic mass of Li = 7]

Answer 1

Answer: (D)

Number of atoms in $1g$ of $Li=\frac{1}{7}\times N_A$
$=0.86\times 10^{23}$
Number of atoms in $1g$ of $Ag=\frac{1}{108}\times N_A$
$=0.056\times 10^{23}$
Number of atoms in $1g$ of $Mg=\frac{1}{24}\times N_A$
$=0.25\times 10^{23}$
Number of atoms in $1g$ of $O_2=\frac{1}{32}\times N_A\times 2$
$=\frac{N_A}{16}=0.37\times 10^{23}$
Maximum number of atoms are present in$1g$ of $Li$.